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Section 17.4 The Cauchy-Riemann equations
Objectives
Determine continuity and differentiability of complex functions.
Use the Cauchy-Riemann equations to characterize when a complex function is holomorphic.
Interpret holomorphic functions as conformal mappings.
Derivative of complex function:
\begin{equation*}
f'(z)=\limit{h\to 0}\frac{f(z+h)-f(z)}{h}
\end{equation*}
Note that \(h\) is complex here! Alternatively:
\begin{equation*}
f'(z_{0})=\limit{z\to z_0}\frac{f(z)-f(z_{0})}{z-z_{0}}
\end{equation*}
Limits are defined exactly as you think they are based on multivariable calculus:
\begin{equation*}
\limit{z\to z_0}f(z)=L
\end{equation*}
means that \(f(z)\) approaches \(L\) as closely as desired when \(z\) approaches \(z_{0}\) along any path.
Some functions aren’t differentiable. Great example is
\(f(z)=\overline{z}\text{:}\) Aside Another fun one is
\(f(z)=|z|^{2}\text{,}\) which is differentiable everywhere for real functions but is differentiable only at
\(z=0\) as a complex function!
\begin{equation*}
\limit{h\to 0}\frac{\overline{z+h}-\overline{z}}{h}=\limit{h\to 0}\frac{\ \ \overline{h}\ \ }{h}
\end{equation*}
If \(h\to 0\) along the real line, this quotient approaches \(1\text{,}\) but if it approaches over the imaginary line, the quotient approaches \(-1\text{.}\) Therefore the limit does not exist, and hence the complex conjugate is not differentiable.... anywhere!
If a function
\(f\) is differentiable at
\(z_{0}\) and at every point in some neighborhood of
\(z_{0}\text{,}\) we say
\(f\) is holomorphic at
\(z_{0}\text{.}\)
If a function \(f(z)=u(x,y)+\ii v(x,y)\) is differentiable at a point, it must satisfy the Cauchy-Riemann equations:
\begin{equation*}
\pdv{u}{x}=\pdv{v}{x}\qquad \pdv{u}{y}=-\pdv{v}{y}
\end{equation*}
Furthermore, if \(u\) and \(v\) are continuous and have continuous first partial derivatives in a domain \(D\text{,}\) then satisfying the Cauchy-Riemann equations at all points of \(D\) implies that \(f\) is holomorphic in \(D\text{.}\)
All the “nice” functions are holomorphic in their domains: polynomial, rational, exponential, trigonometric, logarithmic, inverse trigonometric. (Excluding branch cuts.) This in fact means that all our original derivative formulas from calculus apply!
If
\(f\) is holomorphic in a domain
\(D\text{,}\) then
\(f\) is constant if
\(|f|\) is constant or if
\(f'=0\text{.}\)
A function that is holomorphic at every point in the complex plane is called entire.
Linear approximation:
\begin{equation*}
f(z)=f(z_{0})+f'(z_{0})(z-z_{0})
\end{equation*}
Should be able to relate this to being holomorphic.