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Section 15.3 Surface area
Objectives
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Compute the area of a surface
\(z = f(x,y)\) by integrating a surface-area element over its domain.
-
Relate the surface-area formula to the structure of the arc length formula in one dimension.
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Interpret the integrand as the magnitude of a cross product formed from tangent vectors on the surface.
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Area of the surface \(z=f(x,y)\) over the region \(D\text{:}\)
\begin{equation*}
\iint_{S}\dd{S}=\iint_{D}\sqrt{\qty(\pdv{f}{x})^{2}+\qty(\pdv{f}{y})^{2}+1}\dd{A}
\end{equation*}
Notice similarity with arc length formula.
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Derivation has to do with surface area element:
\begin{align*}
\bv{a} \amp = \qty(\dd{x},0,\pdv{f}{x}\dd{x}) \\
\bv{b} \amp = \qty(0,\dd{y},\pdv{f}{y}\dd{y}) \\
\dd{S} \amp = \norm{\bv{a}\times\bv{b}} = \sqrt{\qty(\pdv{f}{x})^{2}+\qty(\pdv{f}{y})^{2}+1}\dd{A}
\end{align*}