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Section 19.4 Surface integrals
Objectives
Parametrize surfaces in three dimensions using mappings from a planar region.
Evaluate surface integrals of scalar functions using the surface-area element.
Apply surface integrals to compute surface area and mass.
Just as curves can be written as functions of a parameter
\(t\text{,}\) surfaces can be written as functions of two parameters, often called
\(u\) and
\(v\text{.}\)
A few examples:
Sphere of radius \(\rho\text{:}\)
\begin{equation*}
\bv r(\theta,\phi)=(x,y,z)=(\rho\sin\phi\cos\theta,\rho\sin\phi\sin\theta,\rho\cos\phi)
\end{equation*}
Helicoid:
\begin{equation*}
\bv r(u,v)=(x,y,z)=(v\cos u,v\sin u,au)
\end{equation*}
Surface of revolution about \(x\) -axis:
\begin{equation*}
\bv r(u,v)=(x,y,z)=(u,f(u)\cos v,f(u)\sin v)
\end{equation*}
For all of these, \((u,v)\) are points of some domain \(D\text{.}\)
Surface area element:
\begin{equation*}
\dd{S}=\norm{\pdv{\bv{r}}{u}\times\pdv{\bv{r}}{v}}\dd{A}
\end{equation*}
Here, \(\dd{A}=\dd{u}\dd{v}\text{.}\)
Surface area:
\begin{equation*}
S=\iint_{S}\dd{S}=\iint_{D}\norm{\pdv{\bv{r}}{u}\times\pdv{\bv{r}}{v}}\dd{A}
\end{equation*}
Similarly to with line integrals, we can extend this to make the surface integral of a function over that surface:
\begin{equation*}
S=\iint_{S}f\dd{S}=\iint_{D}f(\bv r(u,v))\norm{\pdv{\bv{r}}{u}\times\pdv{\bv{r}}{v}}\dd{A}
\end{equation*}
Notice this is just the next level up of what we already do with line integrals.
If
\(f\) is density, then we can compute mass, center of mass, moment of inertia, etc.
Again, if \(\bv r(u,v)=(x,y,z)\text{,}\) and the Jacobian is
\begin{equation*}
\bv J=\begin{bmatrix}\DS\pdv{x}{u} \amp \DS\pdv{x}{v}\\[2 ex] \DS\pdv{y}{u} \amp \DS\pdv{y}{v}\\[2 ex] \DS\pdv{z}{u} \amp \DS\pdv{z}{v}\end{bmatrix}\text{,}
\end{equation*}
then we end up with \(\sqrt{\abs{\det(\bv J^T\bv J)}}=\norm{\DS\pdv{\bv{r}}{u}\times\dv{\bv{r}}{v}}\text{.}\)