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Section 1.1 Approximating the circle

What is the area of a circle?
You probably already know the formula from previous math classes:
\begin{equation*} A = \pi r^2 \end{equation*}
But have you ever stopped to wonder where that formula comes from?
In the ancient world, mathematicians needed the answer to this question to design things like temples, storage containers, and astronomical instruments. They of course knew how to calculate areas of simple shapes like rectangles and triangles, as well as polygons that could be broken into these shapes. But a circle has no straight sides, so it doesn’t naturally decompose into those familiar pieces.
Put yourself in the place of one of those ancient mathematicians. How might you go about solving this problem?
A natural idea might be to see what pieces you can break a circle into. You might start by slicing it into four equal wedges, as in the figure below. If we rearrange those pieces, alternating between pointing them up and down, we get a shape that resembles a parallelogram.
If we then slice one of those pieces down the middle and move it to the other side, we have a shape with two vertical sides and a bumpy top and bottom.
What if we slice the circle into eight wedges instead of four? If we follow the same process as earlier, the shape we get has smaller, more gentle bumps along the top and the bottom:
If we start with sixteen wedges, the bumps are smaller still:
Each time we increase the number of wedges, the rearranged figure starts to look more and more like a rectangle, with the curved boundary of the original circle being distributed across many tiny pieces.
So here’s an interesting idea: what if we used infinitely many wedges?
In that case, you might imagine that the top and bottom wouldn’t look bumpy at all. You wouldn’t be able to tell the difference between the rearranged figure and a rectangle, no matter how closely you zoomed in. And since area doesn’t change when we just rearrange the pieces, the area of this rectangle should be the same as the area of the original circle.
We can identify that the height of the rectangle is the radius \(r\) of the circle, and the base is half the circumference \(C\) of the circle, since the circle’s boundary has been distributed across the top and bottom of the rectangle. So the rectangle has area
\begin{equation*} \text{Area} = \text{Base} \times \text{Height} = \frac{1}{2} C\cdot r\text{.} \end{equation*}
Notice that we’ve reduced the problem of finding the area of a circle to the problem of finding its circumference. And since the circumference of a circle is proportional to its radius, once we know that constant of proportionality, we can determine the area of a circle from its radius alone. In the exercises below, you’ll see how to find this constant by approximating the boundary of the circle with polygons.
Now, you might be a bit skeptical of this idea of using ‘infinitely many’ wedges. There are a number of questions you might wonder:
  • If the wedges are infinitely thin, how do they contribute anything to the area?
  • Can we really think of the top and bottom as straight lines if they are made up of infinitely many tiny bumps?
  • Is it even valid to use the idea of infinitely many infinitely small wedges in the first place?
If you had any of these concerns, you’re in good company! This idea of using infinitesimal (infinitely small) pieces has long been a controversial topic in mathematics. On one hand, infinity is notoriously difficult to get a handle on; on the other hand, allowing ourselves to work with these infinitesimal ideas has helped us solve a lot of tricky problems throughout history. Out of centuries of wrestling with these ideas came the field that today we call calculus, and that is what we’ll be studying throughout this book. By developing calculus, we’ll be able to find a way to make these intuitive-but-somewhat-vague arguments more precise, which will allow us to use them with confidence to solve problems in a variety of applied contexts.

Exercises Exercises

1.

In this exercise, we will approximate the circumference of a unit circle by inscribing polygons with an increasing number of sides. This method is due to Liu Hui, a Chinese mathematician who lived in the third century AD. It doesn’t require any trigonometry — just the Pythagorean theorem and some algebra.
Aside
(a)
Start with a regular hexagon inscribed in a circle of radius \(1\text{.}\) What is the perimeter of this hexagon?
Hint.
Remember that a regular hexagon has six equal sides and six equal angles. If you split it into six triangles as shown, what kind of triangle do you get?
(b)
Suppose we bisect each of the six arcs of the circle to get a regular \(12\)-sided polygon (a dodecagon) inscribed in the circle, as shown below.
Let’s zoom in on the topmost arc of the circle.
Find the lengths of segments \(OA\text{,}\) \(AB\text{,}\) \(OB\text{,}\) \(BC\text{,}\) and \(AC\text{.}\) Then find the perimeter of the dodecagon.
(c)
Continue this process of bisecting arcs to get a regular \(24\)-sided polygon, then a regular \(48\)-sided polygon, and finally a \(96\)-sided polygon. What do you notice about the perimeters of these polygons?
(Hint: You probably won’t be able to actually draw these polygons. Instead, use the lengths from each step to find the lengths needed for the next step.)
Answer.
\(24\)-sided polygon: perimeter \(\approx 6.265\)
\(48\)-sided polygon: perimeter \(\approx 6.278\)
\(96\)-sided polygon: perimeter \(\approx 6.282\)
These perimeters are getting closer and closer to the circumference of the circle, which is \(2\pi \approx 6.28318\text{.}\)
(d)
You should have found that the perimeters of the inscribed polygons are approaching the number
\begin{equation*} \tau = 6.283185307179586476925286766559\cdots\text{.} \end{equation*}
Since the circle has a radius of \(1\text{,}\) this suggests that the circumference of a circle is equal to \(\tau\cdot r\) for any radius \(r\)
For historical reasons, the more commonly studied ratio is that of the circumference to the diameter, which is half of this number, commonly known as
\begin{equation*} \pi = \frac{\tau}{2} = 3.141592653589793238462643383279\cdots\text{.} \end{equation*}
Show that this leads to the area formula for a circle:
\begin{equation*} A = \pi r^2\text{.} \end{equation*}
(e)
Will the perimeters of the inscribed polygons ever equal the circumference of the circle? Why or why not?

2.

We can also approximate the circumference of a unit circle by circumscribing polygons with an increasing number of sides. These sides are tangent to the circle, meaning they barely touch the circle at a single point. Notice that each tangent line makes a right angle with the radius of the circle where it touches.
(a)
Start by circumscribing a regular hexagon around a circle of radius \(1\text{.}\) What is the perimeter of this hexagon?
(b)
Suppose we bisect each of the six arcs of the circle and construct a tangent line to the circle at each of these points, giving a regular dodecagon circumscribed around the circle, as shown below.
Let’s zoom in again on the topmost arc.
Find the lengths of segments \(AD\) and \(AE\text{.}\) Then find the perimeter of the circumscribed dodecagon.
Hint.
Triangle \(OCD\) is similar to triangle \(EAD\text{.}\)
(c)
Continue this process of bisecting arcs and constructing tangent lines to get a regular \(24\)-sided polygon, then a regular \(48\)-sided polygon, and finally a \(96\)-sided polygon. What do you notice about the perimeters of these polygons?
(d)
How does this method of approximating the circumference compare to the method of inscribed polygons? Do you think they’re guaranteed to give the same result? Why or why not?

3.

Repeat the above exercises, but this time start with an inscribed square and a circumscribed square instead of a hexagon. How do the results compare to the previous exercises?

4.

Remember that the equation of a circle of radius \(1\) in the plane is given by \(x^2 + y^2 = 1\text{,}\) so the upper semicircle has equation \(y = \sqrt{1 - x^2}\text{.}\)
(a)
Fill in the following table of values for points along the upper semicircle.
Table 1.
\(x\) \(y\)
\(-1\)
\(-0.5\)
\(0\)
\(0.5\)
\(1\)
Then use the distances between the points in the table to estimate the circumference of the circle.
(b)
Refine your estimate by breaking subdividing the interval \(-1\le x\le 1\) into eight equal-width segments, then sixteen.
(c)
How does this method compare to the method of inscribed or circumscribed polygons? Do you think they’re guaranteed to give the same result? Why or why not?

5.

The process in the first exercise can be expressed using a recurrence relation as follows: If the perimeter of the inscribed polygon with \(n\) sides is \(P_n\text{,}\) then the perimeter of the inscribed polygon with \(2n\) sides is given by
\begin{equation*} P_{2n} = 2n\sqrt{2 - \sqrt{2 - \left(\frac{P_n}{2n}\right)^2}}\text{.} \end{equation*}
(a)
Use this recurrence relation to verify the results of Exercise 1.
(b)
Develop a similar recurrence relation for the perimeters of the circumscribed polygons and use it to verify the results of Exercise 2.
(c)
Write a computer program to implement these recurrence relations and use it to compute perimeters of inscribed and circumscribed polygons with more and more sides. How do these values compare to \(\tau\) as you increase the number of sides?